Questions about the world of GMAT Math from other sources and general math related questions.
monge.alejandro
Prospective Students
 
Posts: 2
Joined: Tue Nov 15, 2011 8:07 am
 

(3^-2)^-3

by monge.alejandro Tue Dec 06, 2011 9:33 pm

(3^-2)^-3

3^-6
3^-5
3^-1
3^5
3^6

I would think you need to start with parenthesis, so 3^-2=9, which is the same than 3^2; then you multiply by the -3, to equal 3^-6. I think I read too much into it.
jnelson0612
ManhattanGMAT Staff
 
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Joined: Fri Feb 05, 2010 10:57 am
 

Re: (3^-2)^-3

by jnelson0612 Sun Dec 25, 2011 11:48 pm

monge.alejandro Wrote:(3^-2)^-3

3^-6
3^-5
3^-1
3^5
3^6

I would think you need to start with parenthesis, so 3^-2=9, which is the same than 3^2; then you multiply by the -3, to equal 3^-6. I think I read too much into it.


When I have an exponent that is taken to the power of another exponent, you simply need to multiply the two exponents together. Thus, this is 3^(-2 * -3), or 3^6.

Also, I want to clarify 3^-2. Anything to a negative power means take the reciprocal of the base, then apply the positive exponent. So 3^-2 becomes (1/3)^2, thus this expression actually is 1/9.
Jamie Nelson
ManhattanGMAT Instructor