CAT 5/#15
(3^5x + 3^5x + 35x)(4^5x + 4^5x + 4^5x + 4^5x) = ?
A) 12^5x+1
B) 3^15x+4^20x
C) 25^5x
D) 7^35x
E) 25^5x+1
The answer explanation is as follows:
Step 1: (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =
Step 2: 3^5x(1 + 1 + 1) × 4^5x(1 + 1 + 1 + 1) =
Step 3: 3(3^5x) × 4(4^5x) =
Step 4: 3^5x+1 × 4^5x+1 =
Step 5: (3 × 4)^5x+1 =
Step 6: = 12^5x+1
I don't understand what happened between Step 3 and 4. How did the exponent become ^5x+1 for both 3 and 4? What happened to 3^5x and 4^5x?