an equallateral triangle insribed in a circle

by **guest123** Mon Dec 01, 2008 12:55 am

[deleted - source not allowed]

by **Pravin** Mon Dec 01, 2008 3:34 pm

It should be 11.45 units
Given Arc ABC is 24 units arc ABC will make an angle of 240 at center so using formula

(Theeta) X 2X PI X R / 360 = 24 put values and find 2R
2X22XRX240/7X360=24 Check option I think C which is 11 units.

by **guest** Mon Dec 01, 2008 3:41 pm

Pravin Wrote:It should be 11.45 units
Given Arc ABC is 24 units arc ABC will make an angle of 240 at center so using formula

(Theeta) X 2X PI X R / 360 = 24 put values and find 2R
2X22XRX240/7X360=24 Check option I think C which is 11 units.

Agreed on this.

The arc will equal to 2/3 of a circle so the circumfrence is 36. 36 / pi =~11, which is 2r, which is the diameter.

Think the trick is to just translate the problem correctly.

by **Reva** Sun Dec 07, 2008 10:17 pm

[color=black]Praveen, please tell us the logic behind assuming that "Given Arc ABC is 24 units arc ABC will make an angle of 240 at center".

Thanks!

by **JonathanSchneider** Wed Dec 10, 2008 9:22 pm

I had to delete this post. We cannot publish problems from GMATPrep here. Please read the forum rules before posting.