Avg data suff problem

[nipukumar]

I am not sure if General Math is still open, but have seen recent posts and reply in the forum, hence i am posting my query. This is a data sufficiency problem.

Committee A and Committee B , which have no common members, will combine to form Committee C . Does Committee A have more members than Committee B ?

(1) The average (arithmetic mean) age of the members of Committee A is 25.7 years and the average age of the members of Committee B is 29.3 years.

(2) The average (arithmetic mean) age of the members of Committee C will be 26.6 years.

What is the approach here ?

[jnelson0612]

Hi nipukumar,
Will you please provide the source for this problem, as well as the given answer?

Thanks!

[nipukumar]

Hi Jamie,
This one appeared in paper-n-pencil test code 31.

Correct ans is: C (Together)

Thanks,

[pranabiitkgp]

no of members in Committee A is a
and no of members in Committee B is b
(25.7a + 29.3b)/(a+b )= 26.6

you will get a/b and hence which one is greater .so the ans is C.

[gangesh.dubey]

The approach should be as below.

Assuming the number of members in both the commitees are same,then the average age of the commitee C would be (29.3 +25.7)/2 = 27.5
Now,taking both the statements together,as the average age of the combined commitee is 26.6 ,commitee A definitely has more members as 26.6< 27.5

Regards,
Gangesh

[jnelson0612]

Hi Jamie,
This one appeared in paper-n-pencil test code 31.

Correct ans is: C (Together)

Thanks,

Hi, so to clarify, this an official GMAT paper and pencil test?