Rate of a certain chemical reaction is directly proportional to the square of chemial A and inversely proportional to the chemical B. If B is increased by 100%, which of the following is closest to the % changed in concentration of chemical Arequired to keep the fraction rate unchanged.
a. 100% decrease
b. 50% decrease
c. 40% decrease
d. 40% increase
e. 50% increase
question is from prep software.
Ans is d. pls help
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- poonamchiK
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- thoppae.saravanan
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Re: Chemical rkn
Let:
Ca = Chemical A quantity.
Cb = Chemical B quantity.
Ca1 = Change in Chemical A quantity required where Cb is increased.
Cb1 = Change in Chemical B quantity.
Given:
Rate of Chemical reaction = K(Ca^2/Cb) where K is a constant.
Cb1 = 2Cb.
Asked:
Ca1^2/Cb1 = Ca^2/Cb => Ca1^2/2Cb = Ca^2/cb => Ca1 = 1.414Ca
So this means that 40% Ca has to be increased hence option D is the right one.
Ca = Chemical A quantity.
Cb = Chemical B quantity.
Ca1 = Change in Chemical A quantity required where Cb is increased.
Cb1 = Change in Chemical B quantity.
Given:
Rate of Chemical reaction = K(Ca^2/Cb) where K is a constant.
Cb1 = 2Cb.
Asked:
Ca1^2/Cb1 = Ca^2/Cb => Ca1^2/2Cb = Ca^2/cb => Ca1 = 1.414Ca
So this means that 40% Ca has to be increased hence option D is the right one.
2 posts Page 1 of 1