If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?
A. 20
B. 40
C. 50
D. 80
E. 120
The answer to this is D.
I figure it this way:
10C3=120
5*1*8=40
120-40=80
IS taking 5*1*8 right for the total number of combinations with two married people?
Thanks