Hi,
I am making this up, because I wanted to try out different scenarios of selections.
Imagine there are 26 people are at a party. 5 women and the rest are men (so, 21 men). If we were to select a group of 3 people, how many different ways can we select a group where there are at least 2 women.
Here's what I have:
5 women; 21 men
SO: we can have 2 women and 1 man OR 3 women (using the 1 - trick here won't be much help I think because we would need to calculate no women and 1 woman, same story, just an extra step):
If it is 2 women and 1 man:
It is 5C2 * 21C1: so 10 * 21 = 210
If it is 3 women only:
Then it is 5C3 = 10
Together we have 210 + 10 = 220. Am I correct?
Thank you!