doubt on Q 11 work set 2 page 234 Advance quant book

[archit_anand143]

If a is not equal b

Is 1/ (a-b) > ab
1. mod a > mod b
2. a <b

As I understand and read from the explanation given on the solution page its conditional rephrasing question
i.e we must from the any statement know as to whether (a-b)<0 or
(a-b)>0

But the solution in the book si not worked towards finding whether (a-b) > or less than 0 instead plugging of number is used.
Can you pls use show how to use the statement for finding (a-b)> or less than 0 without plugging number.

If we go by the principle of determinig whether a-b>0 or a-b<0 than statement 2 is sufficient but than in statement 1 we get two different conditions i.e a>b which implies a-b>0 and a<-b which implies a+b<0

We are not concerned about a+b<0 hence a-b>0 info suggests that statement 1 too is sufficient.

The rephrasing technique for inequality DS ,described in the book is really helpful.

I encountered another question on Grockit , where the technique could be used but i was not confident of using...

Can you pls help me with it...

If m is not equal to - n
Is [(m-n)/(m+n)] > 1

1. n <0
2 m>0

For the statement to be sufficient we must know whether (m+n)>0 or less than zero but no statement provides that info on combining we get know m-n>0 which is not of our concern, we want to know whether (m+n) is less or greater than zero.

Srry for so long post .
pls help me with the above questions as this is one of the topic, knowledge of which i essential to cross Q 49 mark......


Regards
Archit

[tim]

If a is not equal b

Is 1/ (a-b) > ab
1. mod a > mod b
2. a <b

As I understand and read from the explanation given on the solution page its conditional rephrasing question
i.e we must from the any statement know as to whether (a-b)<0 or
(a-b)>0

But the solution in the book si not worked towards finding whether (a-b) > or less than 0 instead plugging of number is used.
Can you pls use show how to use the statement for finding (a-b)> or less than 0 without plugging number.

No. This one should not be attempted without plugging in numbers..

If we go by the principle of determinig whether a-b>0 or a-b<0 than statement 2 is sufficient but than in statement 1 we get two different conditions i.e a>b which implies a-b>0 and a<-b which implies a+b<0

We are not concerned about a+b<0 hence a-b>0 info suggests that statement 1 too is sufficient.

The rephrasing technique for inequality DS ,described in the book is really helpful.

i'm not sure if there is a question here; if there is, please make it more explicit..

I encountered another question on Grockit , where the technique could be used but i was not confident of using...

sorry, we can't discuss other companies' copyrighted material here. please also note that even if this were an allowed question you should post separate problems in separate threads..

pls help me with the above questions as this is one of the topic, knowledge of which i essential to cross Q 49 mark......

i heartily disagree that there is ANY single topic that is absolutely essential to getting a 49, but it never hurts to learn as much as you can..