Ruben Wrote:Hi All,
Can anyone please help me with this expression?
1-( 1/x-1) + 2/(1-x^2)
Thanks,
Ruben
it's not clear exactly what you want to
do with that expression.
are you trying to put it over a common denominator?
if so, then the common denominator is 1 - x^2, because that's the product (1 - x)(1 + x). note that (x - 1), the denominator of the second fraction, is the negative of (1 - x), so you can rewrite -1/(x - 1) as
+1/(1 - x).
therefore, we have
1 + 1/(1 - x) + 2/((1 - x)(1 + x))
multiply the first fraction by (1 - x)(1 + x) on top and bottom, and multiply the second fraction by (1 + x) on top and bottom:
(1 - x^2)/((1 - x)(1 + x)) + (1 + x)/((1 - x)(1 + x)) + 2/((1 - x)(1 + x))
which simplifies to
(3 + x - x^2) / ((1 - x)(1 + x))
i think that's about as good as it gets.