scott.yin Wrote:ok so given the basic example of 4 available seats on a plane for 7 people. If order did not matter, we sould compute the number of different possibilities as 7!/4!3! ? And if order did it would be 7!/4!?
If order does not matter, we use Pool!/In!Out!. Thus, if we are selecting four people out of seven to sit in the seats, we do indeed have 7!/4!3!, with four people chosen and three people not chosen.
If order matters, we use a slightly different formula: Pool!/Place!Place!Place!Place!Out!. In this case, one person can sit in seat A, one person can sit in seat B, one can sit in seat C, and so on, and three will be left out.
Thus, our formula here is 7!/1!1!1!1!3!, which simplifies to 7!/3!.
Hope this helps!