Had a question with the following problem- the answer listed was C, but I get B:
Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean?
(1) a + e = (3/4)(c + d)
(2) b + f = (7/8)(c + d)
As the explanation states, the question is essentially asking: Is 2(c+d) > a + b + e + f?
With Statement 2, we can substitute for b + f and rephrase the question as: Is (9/8)(c+d) > a + e?
This was said to be insufficient as e could be really large or small compared to the other numbers.
The problem with that explanation is that we know that b > a and f > e because the set of numbers is said to be ascending. So b + f > a + e and, using Statement 2, (7/8)(c+d) > a + e. If a + e is less than 7/8 of c + d, then it must also be less than 9/8 of c + d, since c and d are both positive. So it seems like the answer should be B. Is there something I am missing? Thanks.