by RonPurewal Tue Sep 18, 2007 3:51 am
Guest's setup is correct:
The way there: RATE = 80, TIME = t, DISTANCE = 80t
The way back: RATE = 70, TIME = t + 1/2, DISTANCE = 70(t + 1/2)
Because it's a round trip (same distance there as back), you set the two Distance expressions equal, leading to Guest's equation.
This problem is very amenable to BACKSOLVING: plug the answer choices in and see if they work.
Let's try answer choice C:
* The way there: distance = assumed to be 320, rate = 80, so time = 320/80 = 4 hours
* The way back: distance = assumed to be 320, rate = 70, so time = 320/70 = 4 4/7 hours
* It's not a half-hour difference, so this is the wrong answer.
* The difference is MORE than half an hour, so this choice is TOO LONG of a distance (the longer the distance, the bigger the difference between the two times, since everything is proportional)
Let's try answer choice D:
* The way there: distance = assumed to be 280, rate = 80, so time = 280/80 = 3 1/2 hours
* The way back: distance = assumed to be 280, rate = 70, so time = 280/70 = 4 hours
* It's a half-hour difference, so this is the right answer.