* help?????

[absolute value problem]

If x<0, then [sqrt (-x absolute x )] is
(please note that both variables - minus x and absolute x - come under the root sign)

1
-1
sqrt x
x
-x

[michael_shaunn]

One point I would like to highlight here.Plz make a note of it.

When the question is like:Find x such that x^2=36 then x is either 6 or -6.
When someone asks what is the value of sqrt(36)..then the answer is always positive which is 6 in this case.
Also........sqrt(-x)*sqrt(-x) is not equal to sqrt(-x*-x)=sqrt(x^2)........................(consider x>0)
Rather it is equal to -(sqrt(x^2)).
Consider an example.............sqrt(-6)*sqrt(-6) is not equal to sqrt(-6*-6)=sqrt(36) which gives the answer as 6.The correct answer is -sqrt(36)=-6.

Now lets come back to the question.

For x<0.....absolute x= -x.
Thus the question is to find out sqrt(absolute x*absolute x) which is equal to positive value i.e plus absolte x which is nothing but -x.

[JonathanSchneider]

Please cite the source of this question; otherwise we will have to delete it. Thanks.