by esledge Mon Apr 13, 2009 8:57 pm
This is a neat concept to know: it's Weighted Average (e.g. what is the average number of meat eaters in city A if...). On the GMAT, the weighted average is usually of just two quantities (e.g. % meat eaters for men and for women).
Using your example, the number of people in city A who eat meat is:
0.18M + 0.17W
The percent of people who eat meat is the # of meat eaters/total # of people:
(0.18M + 0.17W)/(M+W)
0.18[M/(M+W)]+0.17[W/(M+W)]
You need to know two principles about this formula.
(1) The result must be between 17% and 18%, inclusive.
(2) If there are more women than men, the result will be closer to 17% (the women's %). If there are more men than women, the result will be closer to 18% (the men's %). If there an equal number of men and women, the result will be exactly 17.5%. Play with some numbers for M and W until this makes sense to you.
Here's bit of an algebraic proof of the principles above. Let's say M + W = T (i.e. total).
% of people who eat meat = 0.18[M/(M+W)]+0.17[W/(M+W)]
% of people who eat meat = 0.18[M/T]+0.17[W/T]
% of people who eat meat = 0.18[M/T]+0.17[(T-M)/T]
% of people who eat meat = 0.18[M/T]+0.17[T/T]-0.17[M/T]
% of people who eat meat = 0.17 + 0.18[M/T] - 0.17[M/T]
% of people who eat meat = 0.17 + 0.01[M/T]
As you can see, since M >=0, the minimum % is 17%. Since the maximum M = T, the maximum % is 18%. 20% is impossible.
Emily Sledge
Instructor
ManhattanGMAT