metman82 Wrote:990 = 9 * 110 = 9 * 2 * 55 = 9 * 2 * 5 * 11
No other primefactors.
Yes, to be clear the prime factorization is 3 * 3 * 2 * 5 * 11.
metman82 Wrote:990 = 9 * 110 = 9 * 2 * 55 = 9 * 2 * 5 * 11
No other primefactors.
JJ32 Wrote:Sorry I understand how to get the prime factors of 990, but I am just confused of what the question is actually asking.
Is it asking for the largest prime factor or if there was another prime factor of 990 in the answer choices could that also be the answer? Just trying to figure out what the question asking?
Thanks and Regards
RonPurewal Wrote:JJ32 Wrote:Sorry I understand how to get the prime factors of 990, but I am just confused of what the question is actually asking.
Is it asking for the largest prime factor or if there was another prime factor of 990 in the answer choices could that also be the answer? Just trying to figure out what the question asking?
Thanks and Regards
the question is asking for the smallest n such that 990 is contained in the product 1 x 2 x 3 x 4 x ... x n.
if n were a smaller factor of 990 then it wouldn't work, because in that case the product 1 x 2 x 3 x 4 x ... x n wouldn't be divisible by 11, and so, a fortiori, it wouldn't be divisible by 990.
jnelson0612 Wrote:madhan, that's certainly one way to look at it. Thanks!