srikanth.devidi Wrote:Is x > y?
1) xy > y^2
2) x(y^2) > y^3
1) xy>y^2
x=5, y=4, then 20>16 (true)-- x>y
x=-5, y=-4, then 20> 16 (true)--- x<y
So A and D are out
2) x(y^2)>y^3
x=5, y=4, then 80>64 (true)--- x>y
x=5, y=-4, then 80>-64 (true)--- x>y
x=-3,y=-4, then -48>-64(true)--- x>y
So B is the answer