If xy^2=1, is x>y?
1) -1<y<1
2) xy<0
Ron, i don't understand how statement 1 is sufficient? from statement 1, y^2 and x both are positive (considering xy^2=1), but how x>y? In statement 1, it says -1<y<1. If put any value of y (-1<y<1) in x=1/y^2, then we get x is always greater than 1, but if we put y=0, then x=undefined. [i]My question is: how undefined is greater than 1? can you clarify it details, please?
Thanks...
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- AsadA969
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inequality problem
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- tim
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Re: inequality problem
The setup told you that xy^2 = 1. This means it is *impossible* for y to be 0, just as surely as if they had said "if y is not equal to 0...".
Tim Sanders
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- RonPurewal
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Re: inequality problem
yeah, you can't make the conditions false.
more importantly, please respect the forum rules. if you post a problem in this folder, you MUST cite the original source of the problem.
we can't comment any further on this problem until you cite the original source. thanks.
more importantly, please respect the forum rules. if you post a problem in this folder, you MUST cite the original source of the problem.
we can't comment any further on this problem until you cite the original source. thanks.
3 posts Page 1 of 1