Hi Ron,
I used your approach in solving quadratic inequalities via plotting the solutions on a number line and then testing cases in the ranges between them. But I am either making a mistake or it isn't working on this problem:
a^3-a^2-2a<0
I factor out an a and then solve the quadratic:
a(a^2 - a - 2) <0
a(a-2)(a+1)<0
So from here I plotted the three possible solutions:
a=0 a=2 a=-1 and started testing the regions for validity.
When I got to the upper range, I tested between 0 and 2 and was super confused. Because for 1/2 it works, for 1 it doesn't. But why? I mean numerically I get why, but I don't understand why the quadratic method did not work?
This question is actually a DS one and the question itself asks if a<0?
So if I wouldn't have tested the 1/2 and just took any number in the range between the two solutions (0 & 2), which would typically be 1 because it's a nice number and I wouldn't see any reason to test half, I would find the statement to be in fact valid when it is not.
Can you explain why the quadratic did not work and if you recommend applying the quadratic to these generally at all? I know there is no cookie-cutter approach and we must stay dynamic, but I definitely NEVER want to use an approach which in some cases leads me to an incorrect answer.
Thanks!
Anjelika