Strategy Guide - Eq., Ineq & VICs
Edition - 4th
Chapter - 5
Page No. - 76
Q. The amount of electrical current that flows through a wire is inversly proportional to the resistance in that wire. If a wire currently carries 4 amperes of electrical current, but the resistance is then cut to one-third of its original value, how many amperers of electrical current will flow through the wire?
Ans. Using 3 as the original resistance and 1 as the new resistance, we can see that the new electrical current will be 12 amperes.
C1 * R1 = C2 * R2
4 * 3 = C2 * 1
12 = C2
Query:
In the question it is said that "The amount of electrical current that flows through a wire is inversly proportional to the resistance in that wire". Therefore, shouldn't C1 and R1 have an inverse relationship? Please explain how we can take "3" as a smart number to solve this problem.