dlginsberg89 Wrote:This question is from Advantage Testing's Math Test 5 Question 24:
Is 4a^2-9b^2<0?
1)2a+3b < 0
2) 2a-3b < 0
-----------------------
1)
4a^2 - 9b^2 < 0
2^2a^2-3^2b^2 < 0
2^2a^2 < 3^2b^2
2a < 2b
2) 2a-3b <0
2a < 3b
The answer is B. I must be missing a rule about square roots that made what I did in (1) wrong. Do you know what it is?
ya, you can't "square root both sides" of an inequality unless you know the signs of both sides.
* if both sides are positive, the inequality points in the same direction as it originally did.
* if both sides are negative, the inequality "flips" and points in the opposite direction.
(these are easy enough to see if you think about specific examples:
4 < 9 and 2 < 3
4 < 9 but -2 > -3.)
in fact, you can't even "square root both sides" of an
equation, much less an inequality, because you still have the same issue (you don't know whether the expressions being squared are positive or negative to begin with).
--
the point of this problem is for you to (
immediately) recognize the "difference of squares" factoring pattern.
i.e., when you see 4(a^2) - 9(b^2), you should factor that into
(2a + 3b)(2a - 3b)
before you even turn your brain on and start thinking.
if you do that factoring, you should be able to see pretty easily how this problem shakes out (provided you understand the basics of the DS format).
--
this may be getting in over our heads here, but you
can "square root both sides" IF you use absolute-value signs once you've done so.
for instance, if you know that a^2 < b^2, then you can say for sure that |a| < |b|.
more on that in our strategy guides if you're interested.