Is x·|y| > y^2?
(1) x > y
(2) y > 0
The correct answer to this question is C. However I don't understand why we will need statement 2 for the statement to be sufficient. Here no matter what happens to Y on the left side is still postive. For example if y=-2 the |-2|=2 so when you divide that to the other side the signs do not flip right? Because when you are dividing by a negative absolute value such as |-2| are you dividing by its postivie absolute value or its negative value?