vak3e Wrote:Q1
(p-1)p(p+1)<0
How do you simplify this? The difficulty is that either only p-1 is negative, or all three parts are negative.
As in the case of other such inequalities, you should ...
... find the points where sign changes can occur,
... break the number line up according to those points,
... test the resulting intervals to see whether the statement works.
In this case, sign changes can happen only at -1, 0, and 1 (the three points where the expression equals zero).
These points divide the number line into four different intervals. Test those intervals:
* p < -1:
Here the statement is true; a product of three negatives is negative.
* -1 < p < 0:
False; it's a product of two negatives and a positive, and so is positive.
* 0 < p < 1:
True; it's a product of one negative and two positives, so it's negative overall.
* p > 1:
False; everything is positive, so the product is positive.
So, the solution is p < -1 or 0 < p < 1.
There's no way to "solve this algebraically" past the point of finding the zero points, since algebra is unable to contend with the changing sign of the product.