shoumik Wrote:Is pq divisble by 168?
1) p is divisble by 14.
2) q is divisble by 12.
I chose C because p and q are different and avoids redundancy. However, after searching google for a bit, I came to find out that the question posted on other forums is different from whats on my NP Guide. Particularly stmt 2; q should be p.
Is that true? If not, can someone explain how C is incorrect?
Thanks.
I am guessing this is from Data Sufficiency. And you are saying that both p and q are required to solve this.
You have to use the method of the prime factorization.
We have to show that pq/168 = integer value
In order to do that the prime factors of 168 must cancel all the prime factors of p and q (at the least).
The prime factors of 168 are 2, 2, 2, 3, 7
When we say that p/14 = int value it means that p has atleast 2 and 7 as prime factors.
The prime factors of p are 2, 7
When we say that q/12 = int value it means that q has atleast 2, 2 and 3 as prime factors.
The prime factors of q are 3 , 2, 2
So the fraction now looks like :
p(2,7) q(3 , 2, 2)
----------------
168(2,2,2,3,7)
So both p and q will be required to cover all the factors in 168.
Hence the answer is C.