OG PS #138

by **GUEST** Tue Sep 11, 2007 10:59 pm

I'm confused with another problem. PS #138. Can someone show me how he/she would approach this?

At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

1/2
2/5
3/5
4/5
5/8

quktf355

by **GMATAttack** Thu Sep 13, 2007 12:45 pm

Night Day
Boxes (3/4)d d

Workers (4/5)w w

Total: (3/5)w* 5/5

* 3/4 x 4/5 = 3/5

THEREFORE:

Day Crew / Total = (5/5) / (3/5)+ (5/5) = (5/5)/(8/5) = 5/8 (E)

Hope that helps. Think of this problem as a rates problem -- a work rate problem. VICs can get confusing with this one.

by **StaceyKoprince** Mon Sep 17, 2007 9:24 pm

Good explanation. Also check out this thread
http://www.manhattangmat.com/forums/og- ... t1206.html

OG PS #138

OG PS #138

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