by StaceyKoprince Thu Apr 26, 2007 3:16 am
You're on the right track. The problem with your original equation is that you included the third item in the ratio, electronics, but the problem says that removing the clothes doubles the ratio of books to clothes. It shouldn't actually change the ratio of books to electronics, because the weight of the books doesn't change, nor does the weight of the electronics. The "doubling" of the ratio is only because the clothing weight went down.
So when you put together your formula, you only want to represent the things that have changed relative to each other: books and clothing. Books are 8x, clothing starts at 5x. Then I remove 4# of clothing, so the clothing becomes 5x-4.
I can write ratios as fractions. So I start with a ratio of 8/5. Then I have a new ratio of 16/5 (because the ratio doubles). I can also, from the last paragraph, write the new ratio as 8x/(5x-4). So now I have two ways to write the same value (the new ratio) and I can set them equal to each other to solve for the unknown multiplier.
Stacey Koprince
Instructor
Director, Content & Curriculum
ManhattanPrep