by StaceyKoprince Thu Dec 06, 2007 10:04 pm
The question doesn't mention that all of the students in the school are in either orchestra or marching band because that's not a true statement for this problem. In fact, the question ("how many students are members of neither the orchestra nor the marching band?") implies that there are some students who do not participate in either activity.
Statement 1 is not useless - 1 is necessary, combined with 2, to solve the problem.
Given:
100 students in marching band
40% of orchestra students are in marching band
how many students are in neither?
There are 4 possibilities:
A) students in orchestra
B) students in marching band
C) students in orchestra AND marching band
D) students in NEITHER orchestra OR marching band
Formula for these "both / neither" problems is:
Total = Group1 + Group2 - Both + Neither
Total = 100 + Group2 - Both + Neither (since I know there are 100 in marching band)
(1) 1000 total students. 1000 = 100 + Group2 - Both + Neither. Insuff. Elim A and D
(2) 50 students in orchestra. So 20 of those are also in marching band. Total = 100 + 50 - 20 + Neither. Insuff. Elim B.
(1) + (2). 1000 = 100 + 50 - 20 + Neither. I can solve for Neither. Suff. Answer is C.
Stacey Koprince
Instructor
Director, Content & Curriculum
ManhattanPrep