Sourch: http://iim-cat-questions-answers.2iim.c ... s-profits/
Question: a is x% of b, b is x% more than a, find x.[/b][/i]
A. 50%
B: 62%
C: 75%
D: 70%
E: None
Solution:
from second part:
b/a=x/100
--->b=ax/100
so, the number is :
(ax+100a)/100................(1)
from first part:
a=(x/100)*b
--->a=(x/100)*a(x+100)/100 [putting the value of b]
--->a=ax(x+100)/10000
--->ax(x+100)=10000a
--->x^2+100x-10000=0 [dividing by a from both side]
--->x^2+2.x.50+50^2=12500
--->(x+50)^2=12500
--->x+50=111.80
--->x=111.80-50
so, x=61.80
in addition, if i use plug in method, it also doesn't make sense.
Hi Ron, How are you. i can not solve this math. is there any mistake in this math?? i used plug in method and general method to solve this math. but every efforts in vain. Some students say: the correct answer is 62% . But i did not get the EXACT figure of this solution. Here, i got approximately 61.80 as correct answer. So, should not it be EXACT figure (like 62%, 70%, etc? also, what is your suggestion about THIS math. i'll be very glad, if i can know what is going here (in this math)...
Thanks....