Wanted to bump this question up mainly because this question is great for back-up method (thanks ron).
Method 3 to doing this problem - just list them!
First, total number of ways of picking 2 people out of 7 = (7*6)/2! = 21.
Next, the number of ways to pick a pair of sibling:
Use a letter to denote each person in the group:
A-B = first 2-sibling group
C-D= second 2-sibling group
E-F-G = 3-sibling group
So your pairs are:
AB
CD
EF
FG
EG
(remember here the positions are interchangeable... so AB and BA are the same pair)
5 total ways to pick two people who are siblings, so you probability of picking a sibling is 5/21.
Applying the 1-x rule: 1 - (5/21) = 16/21 probability of NOT sibling.
Bravo MGMAT - very nice question.