* stuck on an easy question

[tejal777]

If an integer n is divisible by both 6 and 8, then it must also be divisible by which of the following?

(A) 10

(B) 12

(C) 14

(D) 16

(E) 18

OA:B

[africanchallenge]

Hi,

Here is my answer: the Least Common Multiple of 6 and 8 is 24 (6=2 x 3 and 8=2x2x2)

So any number that is divisible by both 6 and 8 will be a multiple of 24, 24 is divisible by 12, and therefore any number divisible by 6 and 8 will be divisible by 12.

Rgds

[esledge]

I would do the problem this way, too. "Must also be divisible by" is code for "LCM."

tejal777, would you please cite the author of the question? For copyright reasons, if we don't have an author cited, we'll have to remove the thread.