chengsaimun Wrote:any one pls ?
Hi:
I'm not great
But here's a shot.
7 people board an airport shuttle with only 3 avail seats, how many DIFFERENT seating arrangements are possible?
The seats in the shuttle are considered different so this is a permutation question
If you anagram, it will be
XYZAAAA
So set of 7, you're picking 3. Order matters so this is a permutation because the seats are different. You see how order matters because XYZ.
7!
4!
You're only looking at the people sitting down on the seats. You don't care about the people standing up. So you want to CANCEL OUT the people standing up. They do not concern us.
When order doesn't matter think of it as
XXXAAAA
So here's 7! / 3!4!
So this example would be if there was that same shuttle, but how many different ways of 3 people being seated can you. Here order doesn't matter. So you see how you're canceling 3 X's and 4 A's?
Its a combination problem.
Honestly, I think the anagram method is actually more confusing than just understanding Combination / Permutations. =P
If this doesn't make sense, I will try to explain it again. But this concept took me forever to learn until someone just told me - dude, just memorize the formulas and you're set.