tim Wrote:I hesitate to say that there is any "best" approach to this problem; different students will find different strategies useful. My advice though would be to make sure you know how to use an algebra approach AND a picking numbers approach effectively on this one. The more you can become familiar with multiple approaches to a given question type, the better prepared you will be for similar questions on the real test.
rustom.hakimiyan Wrote:1) I can follow the MGMAT explanation pretty well but when I started to solve this, I came up with two equations and two unknowns (which didn't yield the correct answer)
EQ 1: xy(Investment)=Investment
EQ 2: x(Investment) + y(Investment) = Investment
My answer was y = -x^2 which is obviously wrong. Can you please comment if this approach was incorrect? I don't normally think of adding/subtracting percentages as 1 + (rise/fall)/100, instead I usually just multiply it by 1, so a 10% increase is 1.1 rather than 1 + (10/100).
2) How would choosing numbers work in this scenario? I wouldn't even know how to pick a number that would work for the first step?
Thanks!
RonPurewal Wrote:rustom.hakimiyan Wrote:1) I can follow the MGMAT explanation pretty well but when I started to solve this, I came up with two equations and two unknowns (which didn't yield the correct answer)
EQ 1: xy(Investment)=Investment
EQ 2: x(Investment) + y(Investment) = Investment
My answer was y = -x^2 which is obviously wrong. Can you please comment if this approach was incorrect? I don't normally think of adding/subtracting percentages as 1 + (rise/fall)/100, instead I usually just multiply it by 1, so a 10% increase is 1.1 rather than 1 + (10/100).
The 1.1 thing is right. But, if you're going to do that algebraically, you HAVE to use 1 ± (p/100), where p is the percent decrease or increase.
I.e., if you want to increase something by 10%, then you have to multiply by 1.10, which is 1 + 10/100.
You can't just convert 10% to a decimal (= 0.10) and multiply by it. That would give you 10% of the original number, which is clearly not what you want here.
For the same reason, if you want to increase something by p%, you can't just multiply by p or p/100%. You don't want to take p% of the number.
Just in case you don't know, here is where this expression comse from:
Original number increased by p%
= original + (p%)(original)
= original + (p/100)(original)
= (1 + p/100)(original)
Without the "1 +" part, it's just a percent OF a number, not a percent change.
10 % Percent increase = (1 + (10/100)) Original Investment
Percent increase = (1.1)Original Investment
So if I tried to solve the equation using the latter of the two -- I would get something along the lines of: Investment(1.x)(.y) = I, solving this ends up being quite messy as I end up with .y = 1/1.x -- I don't really know whether I should multiply by 10 or 100 because I don't know the quantity it has increased by. Am I correct with the above analysis?
RonPurewal Wrote:I'm not Tim.10 % Percent increase = (1 + (10/100)) Original Investment
Percent increase = (1.1)Original Investment
^^ These are correct.So if I tried to solve the equation using the latter of the two -- I would get something along the lines of: Investment(1.x)(.y) = I, solving this ends up being quite messy as I end up with .y = 1/1.x -- I don't really know whether I should multiply by 10 or 100 because I don't know the quantity it has increased by. Am I correct with the above analysis?
"1.x" and "0.y" are not things that exist. You can't insert a variable into an expression as though it were a digit(s).
The non-existence of such things is, in fact, the entire reason why you have to use relatively clunky expressions like 1 ± thing/100.