Hi all, here's a Q that stumped me:
If xy=-8, what is the value of xy(x+y)
1. x-y = 5
I don't understand why 1. would be insufficient to solve this.
If you square xy(x+y)
(xy)^2(x^2 + 2xy + y^2)
Then square x-y
x^2-2xy+y^2 = 25
It's easy to see how we could plug in all the missing pieces and get a value for xy(x+y). I'm guessing there's something wrong with my idea of squaring everything, but as far as I know, it's OK to square stuff w/o hesitation, but taking the square root is what gives you multiple solutions. Can someone please help explain this?! Thank you!
Related subquestion:
If the q had been:
If xy=-6, is xy(x+y)=6
1. x-y = 5
Would this make my approach more valid? If so any ideas why?
Thank you so much guys!