Anonymous Wrote:If (r+s)(r-s) = 7
then,
either
(r+s) = 7 and (r-s) = 1 OR, - I
(r+s) = -7 and (r-s) = -1 OR, -II
(r+s) = 1 and (r-s) = 7 OR, - III
(r+s) = -1 and (r-s) = -7 -IV
From I, r = 4 and s = 3 => r/s = 4/3
From III, r = 4 and s = -3 => r/s = -4/3
Correct ans is D.
hmm.
this is a lot of work; there are at least 2 quick ways to see that statement (2) is insufficient.
one:
note that statement (2) doesn't give any reason why you should have just 4's and 3's.
if r^2 - s^2 = 7, then there's an infinite collection of possible values; for instance, r^2 could be 11 and s^2 could be 4, making r = +/- √11 and s = +/- 2.
or any other values with a difference of seven.
two:
statement (2) only gives information about the SQUARES of r and s. if we only know r^2 and s^2, then it will be impossible to tell whether r and s are positive or negative.
therefore, you're automatically going to have two possible ratios: one in which r and s have the same sign (--> positive ratio), and one in which r and s have opposite signs (--> negative ratio).
either one of these observations constitutes proof that statement (2) is insufficient.