by aerialstrong Mon Sep 24, 2012 12:02 am
I didn't diagram this one. Here'r my thoughts:
The only fixed condition is that T&P are not in the same day, and this is decisive in seperating the days in all following Qs. Remember the fixed condition is important in all could be, must be true, must be false Qs.
19:
Q is about "could be complete" so it must contain all 5 tasks.
Looking for those tasks which only have 2 people do them, so we can easily decide the answer choice needs to have one or the other.
So the answer choice has to contain:
G or L---taping
I or K----Framing
L or O ----Wallboarding
thus we can choose B.
20:
The sequesnce of the tasks
F W T S P
if we know that, 2 crew members, work on 2 days, then we know that they perform 4 tasks, so we know
F W, T, S P
1 , 2, 3
so the 2 crew members shall perform task FWSP, thus choosing D
21:
This one is the same with 19, following the same method, easy.
22:
if S is on the 3rd day, and we know that F must be the 1st day, so the 2nd day could be W and T, so we look for those who do those stuff, and they are G,L,O. so we got the answer E.
23:
this one is quite similar to 20, similar way of thinking. The correct answer choice should represent 4 tasks. so we got answer C and D. But one implied condition here is that, each 2 tasks shall be consecutive, as 2 people in each pair, so C is not right, C represents 3:1.
One piece of info. that I don't find needed is the first sentence---a crew of up to 5 workers...what's the point of this sentence...isn't this info. useless? Anyone?