by ohthatpatrick Fri Feb 15, 2019 3:01 pm
I'm going to just write a scenario with as many people out as I can.
We'll put R and M and T all out (just grabbing names from the first couple rules) and see where that leaves us.
_____________ | R, M, T
The 4th rule would say that L has to be in
L | R, M, T
Can I throw out the remaining people too? S, V, and F?
Almost. If S is out, then V is in. Okay, so how about this:
L, V | R, M, T, S, F
I've scanned the rules to verify this is legal, and it is.
Which answers can be eliminated based on this arbitrary could be true scenario?
(A), (D), and (E).
Looking at (A), we'd say that "F and T aren't a pair of people such that at least one member volunteers". After all, we just saw a possible scenario in which neither of them volunteer.
This question stem is tricky to paraphrase, but it's saying:
1 CORRECT ANSWER: two people, at least one of whom is always IN
4 WRONG ANSWERS: two people who could both be OUT (at the same time)
We just proved that F and T can both be out.
R and S can both be out.
S and T can both be out.
So we're down to (B) and (C).
Let's test (B). Could L and M both be out (or does at least one need to volunteer)?
________ | L, M
Does anything happen when L is out, or when M is out?
According to rule 4, if L is out, then R is in.
According to rule 1, if R is in, then M is in.
So it's impossible for L and M to both be out.
L being out forces R in, and R being in forces M in.
Now we know that (B) is the answer, since L and M cannot both be out.
If a pair of people can't both be out, that means the same thing as "at least one of them will always be in".
We could have disproven (C) by showing that L and V could both be out.
for example,
R M T S | F V L
Hope this helps.