by chike_eze Wed Nov 09, 2011 3:34 am
To be honest, I didn't know where to start with this question -- cos I had no idea what it was referring to.
But after reviewing for 2 days now, I finally recall that I've seen this question before, albeit phrased differently.
It is basically asking, which one of these pairs cannot both not volunteer? i.e., which pair cannot both be out?
If so, then the most efficient path to the correct answer is to attempt to force each pair out. The pair that cannot both be out is the correct answer.
E.g.
A) out: F, T
> in:L out:R,M
> yes no rule violated here
B) out: L, M
> in:R,M,T out:F,V,S,M
O wait, per rule combination, if L is out -> M must be in (and vice-versa)
Stop! that's the answer -- L and M cannot both be out.
No need to test the rest.
For laughs:
C) out: L, V
> in: R,M,T,S out: F,V
> no rule violated here
D) out: R, S
> in:L,V out:R,M,T
> no rule violated here
E) out: S, T
> in:V,L out:R,M,T
> no rule violated here