by Laura Damone Tue May 19, 2020 2:34 am
Sure thing! First, some background on the setup because you need some inferences to start q 17. Nobody confesses after W, and S comes after W, so S doesn't confess. Also, since nobody confesses after W, the last slot can't be a confession. That gives us this:
___ ___ ___ -C ___ ___ -C
___ ___ T ___ ___ ___ ___
We also know T must have exactly two confessions after it. Since 4 and 7 aren't confessions, 5 and 6 must be, giving us this:
___ ___ ___ -C C C -C
___ ___ T ___ ___ ___ ___
We also can infer that T comes before W since there must be confessions after T but can't be any after W. Since W must come before S, who didn't confess, W and S have to be in 6 and 7:
___ ___ ___ -C C C -C
___ ___ T ___ ___ W S
Since we know Z comes before both X and V, Z has got to be 1 or 2. If Z is 2, X and V, then have to be 4 and 5. If Z is 1, X and V could be 4 and 5, or one of them could be 2. If you wanted to, you could frame this at the outset.
Now to 17: If neither X nor V confessed, neither can go in slot 5. That leaves only Y to go in that slot. Y, therefore, confessed. D is the correct answer. The completed diagram would look like this:
___ -C ___ -C C C -C
Z X/V T V/X Y W S
Hope this helps!
Laura Damone
LSAT Content & Curriculum Lead | Manhattan Prep